0=q^2-9q-25

Solution for 0=q^2-9q-25 equation:

0=q^2-9q-25

We move all terms to the left:

0-(q^2-9q-25)=0

We add all the numbers together, and all the variables

-(q^2-9q-25)=0

We get rid of parentheses

-q^2+9q+25=0

We add all the numbers together, and all the variables

-1q^2+9q+25=0

a = -1; b = 9; c = +25;
Δ = b2-4ac
Δ = 92-4·(-1)·25
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{181}}{2*-1}=\frac{-9-\sqrt{181}}{-2}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{181}}{2*-1}=\frac{-9+\sqrt{181}}{-2}
$